Lösung von Aufgabe 1.2 Algebra SoSe 2016: Unterschied zwischen den Versionen

Aktuelle Version vom 8. Mai 2017, 11:44 Uhr

$\begin{pmatrix} \frac{1}{2} \sqrt{2} & -\frac{1}{2}\sqrt{2} \\ \frac{1}{2} \sqrt{2}& \frac{1}{2}\sqrt{2} \end{pmatrix}$

$\begin{pmatrix} 0 & -1 \\ 1& 0 \end{pmatrix}$

$\begin{pmatrix} -\frac{1}{2} \sqrt{2} & -\frac{1}{2}\sqrt{2} \\ \frac{1}{2} \sqrt{2}& -\frac{1}{2}\sqrt{2} \end{pmatrix}$

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@@ Zeile 1: / Zeile 1: @@
-<math>\begin{pmatrix} \frac{1}{2} \sqrt{2} & -\frac{1}{2}\sqrt{2} \\ \frac{1}{2} \sqrt{2}& \frac{1}{2}\sqrt{2} \end{pmatrix}</math>
+<math>\begin{pmatrix} \frac{1}{2} \sqrt{2} & -\frac{1}{2}\sqrt{2} \\ \frac{1}{2} \sqrt{2}& \frac{1}{2}\sqrt{2} \end{pmatrix}</math><br />
+<math>\begin{pmatrix} 0 & -1 \\ 1& 0 \end{pmatrix}</math><br /><br />
+<math>\begin{pmatrix} -\frac{1}{2} \sqrt{2} & -\frac{1}{2}\sqrt{2} \\ \frac{1}{2} \sqrt{2}& -\frac{1}{2}\sqrt{2} \end{pmatrix}</math>
+<iframe scrolling="no" title="Drehung_Matrix" src="https://www.geogebra.org/material/iframe/id/nn4QW9pe/width/1600/height/734/border/888888/smb/false/stb/false/stbh/false/ai/false/asb/false/sri/false/rc/false/ld/false/sdz/false/ctl/false" width="1600px" height="734px" style="border:0px;"> </iframe>
+[[Kategorie:Algebra]]