Lösung von Aufgabe 4.1 S (SoSe 12): Unterschied zwischen den Versionen
Aus Geometrie-Wiki
Wurzel (Diskussion | Beiträge) (→Aufgabe 4.1) |
*m.g.* (Diskussion | Beiträge) (→Aufgabe 4.1) |
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| Zeile 11: | Zeile 11: | ||
[[Category:Einführung_S]] | [[Category:Einführung_S]] | ||
| − | + | ===Lösungsvorschlag 1=== | |
a) | a) | ||
| − | |||
| + | ====Modell 1==== | ||
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| − | + | ====Modell 2==== | |
| − | + | =====Das Modell===== | |
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--[[Benutzer:Nummero6|Tchu Tcha Tcha]] 19:26, 13. Mai 2012 (CEST) | --[[Benutzer:Nummero6|Tchu Tcha Tcha]] 19:26, 13. Mai 2012 (CEST) | ||
| + | =====Kommentar von [[Benutzer:Wurzel|H2O]]===== | ||
| + | B.)da nicht ausgeschlossen ist,dass die Punkte ABCD Teil der Punktmengen einer Geraden sind , trifft Axiom 3 nicht unbedingt zu.--[[Benutzer:Wurzel|H2O]] 16:01, 14. Mai 2012 (CEST) | ||
Version vom 14. Mai 2012, 16:59 Uhr
Inhaltsverzeichnis |
Aufgabe 4.1
Es sei P die Menge der Punkte und G die Menge der Gerade. Wir betrachten folgendes Modell:
P = {A,B,C,D}
G = {{A,B}, {A,C}, {A,D}, {B,C}, {B,D}, {C,D}}
Ich mach mal vorsichtshalber eine Ergänzung: Unter Inzidenz wollen wir die Elementbeziehung verstehen: Also Punkt 
inzidiert mit Gerade 
, wenn er zur Menge der Punkte gehört, die die Gerade bildet.--*m.g.* 13:49, 14. Mai 2012 (CEST)
(War sicher klar, muss man korrekterweise beim Modell aber dazu sagen.)
a) Veranschaulichen Sie das Modell durch eine Skizze.
b) Sind bei dem Modell die Axiome I.0 bis I.3 erfüllt?
Lösungsvorschlag 1
a)
Modell 1
Modell 2
Das Modell
--Tchu Tcha Tcha 19:26, 13. Mai 2012 (CEST)
Kommentar von H2O
B.)da nicht ausgeschlossen ist,dass die Punkte ABCD Teil der Punktmengen einer Geraden sind , trifft Axiom 3 nicht unbedingt zu.--H2O 16:01, 14. Mai 2012 (CEST)
