Lösung von Zusatzaufgabe 11.2P (SoSe 12): Unterschied zwischen den Versionen
Aus Geometrie-Wiki
| Zeile 1: | Zeile 1: | ||
Was ergibt die Verkettung zweier Schubspiegelungen?<br /> | Was ergibt die Verkettung zweier Schubspiegelungen?<br /> | ||
| − | + | gerade sehe ich, dass die verschiebung bei einer schubspiegelung immer parallel zur spielgelgeraden verläuft, die vektoren sind daher alle falsch :-(--[[Benutzer:Studentin|Studentin]] 02:06, 4. Jul. 2012 (CEST) | |
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showResetIcon = "false" enableRightClick = "false" errorDialogsActive = "true" enableLabelDrags = "false" showMenuBar = "false" showToolBar = "false" showToolBarHelp = "false" showAlgebraInput = "false" useBrowserForJS = "true" allowRescaling = "true" /> | ||
<u>braun</u> (bild 1, 2, 3):<br /> | <u>braun</u> (bild 1, 2, 3):<br /> | ||
Version vom 4. Juli 2012, 02:06 Uhr
Was ergibt die Verkettung zweier Schubspiegelungen?
gerade sehe ich, dass die verschiebung bei einer schubspiegelung immer parallel zur spielgelgeraden verläuft, die vektoren sind daher alle falsch :-(--Studentin 02:06, 4. Jul. 2012 (CEST)
braun (bild 1, 2, 3):
erste schubspiegelung
rot (bild 4a und 5a):
zweite schubspiegelung, fall 1: wenn die zweite spiegelgerade im rechten winkel zur ersten spiegelgerade steht, kann das bild auch durch eine drehung durch d1 erfolgen.
blau (bild 4b und 5b):
zweite schubspiegelung, fall 2: wenn die beiden spiegelachsen parallel (oder identisch) zueinander sind, kann das bild auch durch verschiebung dargestellt werden.
grün (bild 4cund 5c):
zweite schubspiegelung, fall 3:zwei spiegelgeraden weder senkrecht noch parallel: drehung durch d2
--Studentin 02:00, 4. Jul. 2012 (CEST)
