Kantenlängen der Schlüsselbox: a= 17,6cm; b= 12,4cm; c= 5,5cm
Volumen: V=a∗b∗c
V = 17,6cm ·12,4cm ·5,5cm = 1200,32 cm³
1200,32cm3÷1000= 1,20032dm3 = 1,20032 l